![How do you graph \\[y = \\sqrt {x + 1} \\], compare it with the parent graph and what is the domain and range? How do you graph \\[y = \\sqrt {x + 1} \\], compare it with the parent graph and what is the domain and range?](https://www.vedantu.com/question-sets/2b11c6d3-8502-400b-bd3b-0c13c7f7d42a2920047683162192290.png)
How do you graph \\[y = \\sqrt {x + 1} \\], compare it with the parent graph and what is the domain and range?
![Find the volume of the solid obtained by rotating the region bounded by y= sqrt(x-1), y=0, and x=7 about the x-axis. | Homework.Study.com Find the volume of the solid obtained by rotating the region bounded by y= sqrt(x-1), y=0, and x=7 about the x-axis. | Homework.Study.com](https://homework.study.com/cimages/multimages/16/studycom_graph-5_450x3984325813456128839910.jpg)
Find the volume of the solid obtained by rotating the region bounded by y= sqrt(x-1), y=0, and x=7 about the x-axis. | Homework.Study.com
![SOLVED: find the area between two curves y= sqrt(x-1) (the square root is over the whole term) x-y=1 SOLVED: find the area between two curves y= sqrt(x-1) (the square root is over the whole term) x-y=1](https://cdn.numerade.com/ask_previews/ae34200a-5889-44c4-be2e-2c9009908b3f_large.jpg)
SOLVED: find the area between two curves y= sqrt(x-1) (the square root is over the whole term) x-y=1
![The region bounded by the curves y = 1 + sqrt(x), y = 1 - sqrt(x), and x=1, is revolved about the y-axis. Find the volume of the resulting solid by a) The region bounded by the curves y = 1 + sqrt(x), y = 1 - sqrt(x), and x=1, is revolved about the y-axis. Find the volume of the resulting solid by a)](https://homework.study.com/cimages/multimages/16/graph_of_region_r6402214326116991363.png)
The region bounded by the curves y = 1 + sqrt(x), y = 1 - sqrt(x), and x=1, is revolved about the y-axis. Find the volume of the resulting solid by a)
![definite integrals - The region between curves $y= {\sqrt x}$ , $0≤x≤4,y=1,x=4$ is revolved about $y=1$. Find the volume of a generated solid. - Mathematics Stack Exchange definite integrals - The region between curves $y= {\sqrt x}$ , $0≤x≤4,y=1,x=4$ is revolved about $y=1$. Find the volume of a generated solid. - Mathematics Stack Exchange](https://i.stack.imgur.com/v1Gpt.png)